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Type of site | Problem Solving Website for Computational Mathematics |
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Created by | Colin Hughes |
Website | projecteuler.net |
Commercial | No |
Registration | Free |
Launched | 5 October 2001 |
Project Euler (named after Leonhard Euler) is a website dedicated to a series of computational problems intended to be solved with computer programs.[1][2] The project attracts graduates and students interested in mathematics and computer programming. Since its creation in 2001 by Colin Hughes, Project Euler has gained notability and popularity worldwide.[3] It includes 800 problems as of 30 May 2022,[4] with a new one added approximately every week.[5] Problems are of varying difficulty, but each is solvable in less than a minute of CPU time using an efficient algorithm on a modestly powered computer.[6] As of 27 April 2021, Project Euler has more than 1,000,000 users who have solved at least one problem, in over 100 different programming languages.[7]
A forum specific to each question may be viewed after the user has correctly answered the given question.[6] Problems can be sorted on ID, number solved and difficulty. Participants can track their progress through achievement levels based on the number of problems solved. A new level is reached for every 25 problems solved. Special awards exist for solving special combinations of problems. For instance, there is an award for solving fifty prime numbered problems. A special "Eulerians" level exists to track achievement based on the fastest fifty solvers of recent problems so that newer members can compete without solving older problems.[8]
The first Project Euler problem is Multiples of 3 and 5
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
Although this problem is much simpler than the typical problem, it serves to illustrate the potential difference that an efficient algorithm makes. The brute-force algorithm examines every natural number less than 1000 and keeps a running sum of those meeting the criteria. This method is simple to implement, as shown by the following pseudocode:
total := 0 for NUM from 1 through 999 do if NUM mod 3 = 0 or NUM mod 5 = 0 then total := total + NUM return total
For harder problems, it becomes increasingly important to find an efficient algorithm. For this problem, we can reduce 1000 operations to a few by using the inclusion–exclusion principle and a closed-form summation formula.
Here, [math]\displaystyle{ \mathrm{sum}_k(n) }[/math] denotes the sum of multiples of [math]\displaystyle{ k }[/math] below [math]\displaystyle{ n }[/math]. In big O notation, the brute-force algorithm is [math]\displaystyle{ O\bigl(n\bigr) }[/math] and the efficient algorithm is [math]\displaystyle{ O\bigl(1\bigr) }[/math] (assuming constant time arithmetic operations).
![]() | Original source: https://en.wikipedia.org/wiki/Project Euler.
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